If x + y + z = 1, then 1-3x2 -3y2-3z2 + 2x3 + 2y3 +2z3 is equal to
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Answered by
1
= 1-6x-6y-6z+6x+6y+6z
= 1-6( x+y+z-x-y-z)
= 1-6[ 1-(x+y+z)]
= 1-6[ 1-1]
= 1-6[ 0 ]
= -5[ 0]
= 0
= 1-6( x+y+z-x-y-z)
= 1-6[ 1-(x+y+z)]
= 1-6[ 1-1]
= 1-6[ 0 ]
= -5[ 0]
= 0
Answered by
0
this is maths so you have dout
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