if x+y+z=1, xy+yz+zx= -1 ,find x²+y²+z²
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Answer:
x²+y²+z²=3
Step-by-step explanation:
x+y+z=1
Squaring on both the sides
(x+y+z)²=(1)²
x²+y²+z²+2xy+2yz+2zx=1
x²+y²+z²+2(xy+yz+zx)=1
x²+y²+z²+2(-1)=1
x²+y²+z²-2=1
x²+y²+z²=1+2
x²+y²+z²=3
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