Question

If x+y+z=10 and x^2+y^2+z^2=40 find xy+yz+zx and x^3+y^3+z^3-3xyz

Answer 1

Step-by-step explanation:

x + y + z = 10

वर्ग करने पर

(x + y + z)² = 100

x²+y²+z²+2xy+2yz+2zx = 100

40 + 2(xy+yz+zx) = 100

2(xy+yz+zx) = 60

xy+yz+zx = 30

x³ + y³ + z³ - 3xyz

(x+y+z)(x²+y²+z²-(xy+yz+zx))

10(40 - 30)

10 * 10 = 100