Question

If X + Y + Z = 14 and xy+yz+zx=3 then find x³+y³+z³-3xyz​

Answer 1

Step-by-step explanation:

(x+y+z)²=x²+y²+z²+2(xy+yz+zx)

(14)²=x²+y²+z²+2.3

196=x²+y²+z²=6

x²+y²+z²=190

x³+y³+z³-3xyz

=(x+y+z)(x²+y²+z²-xy-zx-zx)

=14(190-3)

=14×187

=2618

Answer 2

Hello Mate!!

Your answer is attached in this photo.

I hope it's helpful for you.