Math, asked by vaibhav789, 1 year ago

If (x+y-z)=2 and (xy-yz-zx)=-5. Find the value of x^2+y^2+z^2.

Answers

Answered by parisakura98pari
1
(x +  y - z) ² = x² + y ² + z² +2( xy - yz -zx)
(2)² = x² + y² + z² + 2(-5) ⇒ x² + y² + z² = 4 + 10 = 14
hope this  helps.
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