Question

if x+y+z=22, XY+yz+zx=35. find the value of (x-y)^2+(y-z)^2+(z-x)^2​

Answer 1

Answer:

hey mate here is ur answer hope u find it helpful

Step-by-step explanation:

kindly follow me for any maths related queries

Answer 2

Answer:

(x+y+z)²=x²+y²+z²+2xy+2yz+2xz

(x+y+z)²-2(xy+yz+xz)=x²+y²+z²......

(22)²-2(35)=414......(1)

x²+y²+z²=414

now,

(x-y)²+(y-z)²+(z-x)²

= x²+y²-2xy + y²+z²-2zy+z²+x²-2xz

2x²+2y²+2z²-2(xy+yz+zx)

2(x²+y²+z²) -2(xy+yz+xz)

2(414)-2(35)

758...

therefore 758 is the answer

hope it helps

please mark as brainliest