Question

If x + y – z = 4 and x2 + y2 + z2 = 38, then find the value of xy – yz – zx

Answer 1

the answer is 38
hope it helps

Answer 2

Answer:

(a+b+c)²=a²+b²+c²+2(ab+bc+ca)[We know that]

Now do the same using the problem,

=>(x+y-z)²=x²+y²+(-z²)+2(xy+y(-z)+(-z)x)

=>4²=38+2(xy-yz-zx)

=>16=38+2(xy-yz-zx)

=>2(xy-yz-zx)=16-38=-22

=>xy-yz-zx=-11(Ans.)

Hope it helps you.

If it helps you, please mark this as the brainliest answer.

Thank You!