if x+y-z=4and x^2+y^2+z^2=50 find the value of xy-yz-zx
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(x+y-z)² = x²+y²+z²+2(xy-yz-zx)
4²=50+2(xy-yz-zx)
xy-yz-zx=-34\2=-17 ans
4²=50+2(xy-yz-zx)
xy-yz-zx=-34\2=-17 ans
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