if x+y+z=5 and xy+yz+zx=10then find x³+y³+z³-3xyz
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If x + y + z = 5, (x + y + z)² = x² + y² + z² + 2(xy +yz + zx) 5² = x² + y² + z² + 2(10) 25-20 = 5= x² + y² + z² x³ + y³ + z³ - 3xyz = (x + y +z)(x² + y² + + z² - xy - yz - zx) = (5)(5 - 10) = 5x -5 = 25
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