Math, asked by praveen9092, 11 months ago

If (x+y+z)=6 and xy+yz+zx =1 find xsquare +ysquare+zsquare

Answers

Answered by krismishra6
0

Answer:

34

Step-by-step explanation:

xy+yz+xz=1

2xy+2yz+2xz=2

(x+y+z)^2=6^2=36

x^2+y^2+z^2+2xy+2yz+2xz=36

x^2+y^2+z^2+2=36

x^2+y^2+z^2=34

Mark it brainliest

Answered by lakshyatmr10
1

One step towards learning.

Attachments:
Similar questions