If (x+y+z)=6 and xy+yz+zx =1 find xsquare +ysquare+zsquare
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Answer:
34
Step-by-step explanation:
xy+yz+xz=1
2xy+2yz+2xz=2
(x+y+z)^2=6^2=36
x^2+y^2+z^2+2xy+2yz+2xz=36
x^2+y^2+z^2+2=36
x^2+y^2+z^2=34
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