Question

If x + y + z = 9 and both y and z are positive integers
greater than zero, then the maximum value x can
take is
(Campus Recruitment, 2006)
(a) 3
(6) 7
(6) 8
(d) Data insufficient​

Answer 1

Given info : If x + y + z = 9 and both y and z are positive integers greater than zero.

To find : the maximum value of x can take is..

solution : a/c to question, y and z are positive integers greater than zero.

so, y > 0 and z > 0

here, x + y + z = 9

⇒x = 9 - (y + z)

now here you have to find maximum value of x so value of (y + z) must be minimum.

but y > 0 , z > 0 and both are integers.

we know, after zero , 1 is the smallest positive integer, isn't it ?

to make it minimum, we should take y = z = 1

therefore (y + z) = 2

now x = 9 - 2 = 7

Therefore the maximum value of x can take, is 7.

Answer 2

Answer:

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