If x+y+z=9 and xy+yz+2x=23.Find x3+y3+z3×3xyz.
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Justification:
-> (x3 + y3 + z3 - 3xyz)
= (x + y + z) (x2 + y2 + z2 - xy - yz - zx)
= (x + y + z) [(x + y + z)2 - 3(xy + yz + zx)]
= 9 x (81 - 3 x 23)
= (9 x 12)
= 108
if it is correct then mark as brilliancy..please
-> (x3 + y3 + z3 - 3xyz)
= (x + y + z) (x2 + y2 + z2 - xy - yz - zx)
= (x + y + z) [(x + y + z)2 - 3(xy + yz + zx)]
= 9 x (81 - 3 x 23)
= (9 x 12)
= 108
if it is correct then mark as brilliancy..please
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