Question

If x + y +z=9 and xy+yz + zx=23, the
value of (x^3 +y^3+ z^3 - 3xyz) = ?​

Answer 1

Answer:

x+y+z=9

(x+y+z)^2=81

x^2+y^2+z^2+2(xy+yz+zx)=81

x^2+y^2+z^2+2(23)= 81

81-46

=35

x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2)-(xy+yz+zx)

=(9)(35-23)

=9 (12)

=108

Hope it Helps!