What are two consecutive multiples of six whose sum is 138?
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Answered by
1
Let first no be 6x
and second is = 6x +6
their sum is = 138
6x + 6×+6 = 138
12x +6=138
12×=138-6
12×=132
×=132/12
×=11
first is 6x= 6× 11= 66
second is 6x + 6 = 6× 11 + 6 = 72
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Answered by
0
X + (x+6) = 138
2x + 6 = 138
2x = 138 - 6
= 132
:. X, first multiple = 132/2 = 66
Therefore other multiple= 138-66= 72
;) hope it helps bro : }=
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