Question

if x+y+z=9 , xy+yz+zx=23 , x^2+y^2+z^2=40 find x3+y3+z3-3xyz

Answer 1

Answer:

153

Step-by-step explanation:

i hope this is helpful for you

Answer 2

Formula :-

You must know that

x³ + y³ + z³ - 3xyz

= (x + y + z)(x² + y² + z² - xy - yz - zx)

Calculation :-

Substituting the values in the given formula, we get

x³ + y³ + z³ - 3xyz = (9)(40 - 23)

= 9 × 17

= 153

This is the required answer

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