Question

if x, y,z and w be the digit of a number beginning from the left, the number is

Answer 1

The answer is given below :

Any four digit number is 1234.

Now, 1234

= 1×1000 + 2×100 + 3×10 + 4×1

The value of any digit at ones place is
(1×that digit),

The value of any digit at tens place is
(10×that digit),

The value of any digit at hundreds place is
(100×that digit) and

The value of any digit at thousands place is
(1000×that digit).

In this problem, the digits of the number from the left are x, y, z and w respectively.

So, x is at thousands place, y is at hundreds place, z is at tens place and w is at ones place.

Thus, the required number be

= (1000×x) + (100×y) + (10×z) + (1×w)

= (1000x + 100y + 10z + w) [Answer]

Thank you for your question.