If x,y,z are in A.P .then prove that..........guys please help me I need it's proofing pattern.... please help
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it is given that x,y,z are in AP .. DIVIDE ALL OF THEM BY XYZ . IT WILL GIVE YOU 1/YZ, 1/ZX, 1/XY are in AP.. HOPE it helped.
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★ ARITHMETIC PROGRESSION ★
If An AP is subtracted , added , multiplied or divided uniformly by any integral real number, then the AP will not be changed
Aslike , it'll remain ARITHMETIC PROGRESSION only :
x / xyz , y/ xyz , z/ xyz
1/yz , 1/xz , 1/xy will remain in arithmetic progression
Here , xyz is also a constant , Hence , The above result is stated according to the above application
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
If An AP is subtracted , added , multiplied or divided uniformly by any integral real number, then the AP will not be changed
Aslike , it'll remain ARITHMETIC PROGRESSION only :
x / xyz , y/ xyz , z/ xyz
1/yz , 1/xz , 1/xy will remain in arithmetic progression
Here , xyz is also a constant , Hence , The above result is stated according to the above application
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
selena17:
thanks for answering
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