If x,y,z are in AP, prove that (x+2y-z)(2y+z-x)(z+x-y)=4xyz
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Answer:
Given that x, y, z are in ap
Therefore x+z=2y
Lhs=(X+2y-z) (2y+z-x)(z+x-y)
Putting the value of 2y
(X+X+z-z) (X+z+z-x) (2y-y)
(2x) (2z) (y)
4xyz=rhs
Hence proved
Step-by-step explanation:
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