if x,y,z are in AP then find the value of (x+y-z) (-x+y+z)
Answers
Answered by
259
X,Y,Z are in AP
then y-x=z-y
2y=x+z
y=x+z/2
According to question
(x+y-z)(-x+y+z)
x-z+x+z (-x+x+z +z)
2 2
(2x-2z+x+z) (x+z+2z-2x)
2 2
1/4 (3x-z)(3z-x)
then y-x=z-y
2y=x+z
y=x+z/2
According to question
(x+y-z)(-x+y+z)
x-z+x+z (-x+x+z +z)
2 2
(2x-2z+x+z) (x+z+2z-2x)
2 2
1/4 (3x-z)(3z-x)
kaushikravikant:
your welcome
Answered by
77
x,y,z...
d=common difference
x+d=y
x+2d=z
x+y=x+x+d
(x+y-z)=x+x+x+d-x+2d=3x+d-x+2d=2x-d
(-x+y+z)=-x+x+d+x+2d=x+3d
so
(x+y-z) (-x+y+z)=(2x-d) (x+3d)
d=common difference
x+d=y
x+2d=z
x+y=x+x+d
(x+y-z)=x+x+x+d-x+2d=3x+d-x+2d=2x-d
(-x+y+z)=-x+x+d+x+2d=x+3d
so
(x+y-z) (-x+y+z)=(2x-d) (x+3d)
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