if x,y,z are sides of a triangle and y^2+z^2=x^2 name the type of triangle
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we know that By Pythagoras theorem,
base ^ 2 + height ^2 = hypotenuse ^ 2.
thus, y^2 + z^2 = x^2
Hence, sum of square of any two sides of a ∆
is equal to the square of third side.
Thus, we can infer that the given ∆ is right angled ∆.
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