If x y z are the three factors of a^3-7a-6, then the value of x+y+z will be
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Answered by
1
a^3-7a-6 have roots x, y and z
x+y+z= -q/p
and q=0
pa^3+qa^2+ra+s=0
x+y+z=0
x+y+z= -q/p
and q=0
pa^3+qa^2+ra+s=0
x+y+z=0
Answered by
1
Answer:
3a
Step-by-step explanation:
(a+1)(a2−a−6)
(a+1)(a+2)(a−3)
Now, sum of factors
(a+1)+a+2+a−3=3a
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