if x + y + z is equal to 1 x y + y z + z x is equal to -1 and x y z is equal to minus 1 find the value of x square + y square + z square
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(x+y+z)^2=x^2+y^2+z^2+2(xy+yz+zx)
1=x^2+y^2+z^2+2(-1)
x^2+y^2+z^2=3
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