if X + Y + Z is equal to 12 and X square + Y square + Z square is equal to 64 then find xy + Y Z plus ZX
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Step-by-step explanation:
x+y+z=12
(x+y+z)²=12²
x²+y²+z²+2(xy+yz+zx)=144
64+2(xy+yz+xz)=144
xy+yz+xz=144-64/2
=80/2=40
kalyaniprasad8:
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