Question

if x1 and x2 satisfythe equation 2^2x-8.2^x+12=0 then find x1+x2

Answer 1

Answer:

Assume that,

2^x = p

Then,

p^2 - 8p + 12 = 0

p^2 - 2p - 6p + 12 = 0

p ( p - 2 ) - 6 ( p - 2 ) = 0

( p - 6 ) ( p - 2 ) = 0

p = 6 , 2

now,

2^x1 = 6 and 2^x2 = 2

2^x1 + 2^x2 = 6 + 2

x1 + x2 = 8

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Answer 2

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