If x²+1÷x²=18. Find Value Of x+1÷x And x-1÷x
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Answered by
3
Step-by-step explanation:
Given Equation is x^2 + 1/x^2 = 18
= > x^2 + (1/x^2) = 2 + 16
= > x^2 + (1/x^2) - 2 = 16
We can write it as,
= > x^2 + (1/x^2) - 2 * x * (1/x) = 16
We know that a^2 + b^2 - 2ab = (a - b)^2
= > (x - 1/x)^2 = 16
Answer +4,-4
Answered by
7
Answer:
Thanks...................
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