Math, asked by jishita907, 8 months ago

If x²+1÷x²=18. Find Value Of x+1÷x And x-1÷x​

Answers

Answered by seganesakumar
3

Step-by-step explanation:

Given Equation is x^2 + 1/x^2 = 18

= > x^2 + (1/x^2) = 2 + 16

= > x^2 + (1/x^2) - 2 = 16

We can write it as,

= > x^2 + (1/x^2) - 2 * x * (1/x) = 16

We know that a^2 + b^2 - 2ab = (a - b)^2

= > (x - 1/x)^2 = 16

Answer +4,-4

Answered by Aryan45321
7

Answer:

Thanks...................

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