If x²+1/x²=27,find the value of 3x³+5x-3/x³-5/x. please answer fast
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x²+1/x²=27
or, (x-1/x)²+2.x.1/x=27
or, (x-1/x)²=27-2
or, (x-1/x)²=25
or, x-1/x=5, (neglecting the negative sign)
∴, 3x³+5x-3/x³-5/x=3(x³-1/x³)+5(x-1/x)=3{(x-1/x)³+3.x.1/x(x-1/x)}+5.5= 3{(5)³+3.5}+25=3(125+15)+25=3.140+25=420+25=445
or, (x-1/x)²+2.x.1/x=27
or, (x-1/x)²=27-2
or, (x-1/x)²=25
or, x-1/x=5, (neglecting the negative sign)
∴, 3x³+5x-3/x³-5/x=3(x³-1/x³)+5(x-1/x)=3{(x-1/x)³+3.x.1/x(x-1/x)}+5.5= 3{(5)³+3.5}+25=3(125+15)+25=3.140+25=420+25=445
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Step-by-step explanation:
we need equation
(x-1/x)^3
x^2+1/x^2
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