Question

If x2+1/x2=47 find the value of (x+1/x)​

Answer 1

Answer:

If

x2+1x2=47

(x+1x)2=x2+1x2+2⋅x⋅1x=x2+1x2+2

Substituting the value of x2+1x2=47

(x+1x)2=47+2=49

x+1x=√49=7

(√x+1√x)2=(√x)2+(1√x)2+2⋅√x⋅1√x

=x+1x+2

=7+2=9

Therefore,

(√x+1√x)2=9

⇒, √x+1√x=√9=3