K.E of particle executing shm is 16J when at mean position if amplitude is 25cm and mass is 5.12kgthen time period is
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Explanation:
- Since KE is max at the mean position, KE=1÷2 kA²
- And also K=w²m
- so 16= 1/2 *w²mA²
- W²=32/[(25*10^-2)²*5.12]
- w²=100
- w=2π/T
- so w=10 so 2π/T= 10
- so T=0.62
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