If x2×1/x2 =47 Fong the value of x3/x3
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Hi,
x²+1/x² =47
Add 2(x*1/x) on sides,
x²+1/x²+2=47+2
(x+1/x)² =49
(x+1/x) =√49
x+1/x =7
Then, cube on both sides,
(x+1/x)³=7³
x³+1/x³+3(x*1/x){x+1/x} =343
x³+1/x³+3{7}=343
x³+1/x³+21=343
x³+1/x³=343-21
x³+1/x³=322
I hope this much will help you
- by Abhay
x²+1/x² =47
Add 2(x*1/x) on sides,
x²+1/x²+2=47+2
(x+1/x)² =49
(x+1/x) =√49
x+1/x =7
Then, cube on both sides,
(x+1/x)³=7³
x³+1/x³+3(x*1/x){x+1/x} =343
x³+1/x³+3{7}=343
x³+1/x³+21=343
x³+1/x³=343-21
x³+1/x³=322
I hope this much will help you
- by Abhay
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