Math, asked by sohailraja71, 11 months ago

if x²+1/x²=51 ,then find the value of x²-1/x²​

Answers

Answered by deepikavihan
0
x^2+1=51x^2 then1=51x^2-x^2then 1= 50x^2 x^2=1/50 then putting value in x^2-1/x^2 we get value = -49
Answered by 22072003
2
\tt{Given \ :}


\tt{x^2 + {\dfrac{1}{x^2}} = 51}


\tt{Now,}


\tt{Squaring \ of \ x^2 - {\dfrac{1}{x^2}}, \ we \ get}


\tt{ (x^2 - {\dfrac{1}{x^2}})^2 = x^2 + {\dfrac{1}{x^2}} - 2(x)({\dfrac{1}{x}})}


\tt{(x^2 - {\dfrac{1}{x^2}})^2 = 51 - 2}


\tt{(x^2 - {\dfrac{1}{x^2}})^2 = 49}


\tt{x^2 - {\dfrac{1}{x^2}} = {\sqrt{49}}}


\tt{x^2 - {\dfrac{1}{x^2}} = 7}
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