If x²+1/x²=7 and x≠0;find the value of:7x³+8x_7/x³_8/x
karanchoudhary42:
haa
question repeat kroo yaha prr acche se likhnaa
If x²+1/x²=7 and x≠0;find the value of:7x³+8x-7/x³-8/x
okk
do fast
7x³+ (8x-7)/x³ -8x
kya hai
question ki pic post krr doo
bcz ese tumhare brackets mujhe smjh mei nhi a aa rhe
i promise pkaa solve krrungi then
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![6 \sqrt[6 |0 \leqslant { { \frac{2 \sqrt[ {25 {. \frac{2. |222263233 \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?} | }{?} }^{?} \times \frac{?}{?} }^{?} ]{?} }{?} \times \frac{?}{?} }^{?} }^{2} | ]{?}](https://tex.z-dn.net/?f=6+%5Csqrt%5B6+%7C0+%5Cleqslant++%7B+%7B+%5Cfrac%7B2+%5Csqrt%5B+%7B25+%7B.+%5Cfrac%7B2.+%7C222263233+%5Ctimes+%5Cfrac%7B%3F%7D%7B%3F%7D++%5Ctimes+%5Cfrac%7B%3F%7D%7B%3F%7D++%5Ctimes+%5Cfrac%7B%3F%7D%7B%3F%7D+%7C+%7D%7B%3F%7D+%7D%5E%7B%3F%7D++%5Ctimes+%5Cfrac%7B%3F%7D%7B%3F%7D+%7D%5E%7B%3F%7D+%5D%7B%3F%7D+%7D%7B%3F%7D++%5Ctimes+%5Cfrac%7B%3F%7D%7B%3F%7D+%7D%5E%7B%3F%7D+%7D%5E%7B2%7D+%7C+%5D%7B%3F%7D+ "6 \sqrt[6 |0 \leqslant { { \frac{2 \sqrt[ {25 {. \frac{2. |222263233 \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?} | }{?} }^{?} \times \frac{?}{?} }^{?} ]{?} }{?} \times \frac{?}{?} }^{?} }^{2} | ]{?}")
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