If x² + 1/x² = 79, find the value of x + 1/x
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Given : x² + 1/x² = 79
We know that, (x + 1/x)² = x² + (1/x)² + 2 × x × 1/x
[By using identity , (a + b)² = a² + b² + 2ab]
(x + 1/x)² = x² + (1/x)² + 2
(x + 1/x)² = 79 + 2
(x + 1/x)² = 81
(x + 1/x) = ± √81
[Taking square root on both sides]
x + 1/x = ± 9
Hence the value of x + 1/x is ± 9.
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