In the fig diameter AD =12cm and diameter CD =4cm. Observe the fig. And find Area of non shaded portion,seg AD is the daimeter seg AB, seg AC,seg BD & seg CD are the diameter of semicircles. A,B ,C,D are collinear points. Diameter CD =diameter AB .
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96pi
Step-by-step explanation:
I call these Area of a Shaded Region Questions.
Ashaded = Abig - Alittle
This question is actually a nested shaded region question, so you have to do that formula twice.
The Big Area is easy, that's pir^2 = pi (12^2) = 144 pi
now you need to subtract out the little shapes.
If you imagine the shaded region as 2 semi cirlces with a radius of 8, then that area is = 64pi.
However, you have to account for the 2 white semi-circles.
144pi - (64pi - 16 pi) = 96 pi
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