Question

If x2-15/x=4 and x≠3 find x(x+1)(x+2)(x+3)=?a)12 b)15 c)21 d)27

Please give solution this question
**CAT EXAM**

Answer 1

Answer:

option b = 15

Step-by-step explanation:

If x2-15/x=4 and x≠3 find x(x+1)(x+2)(x+3)=?a)12 b)15 c)21 d)27  

Please give solution this question  

**CAT EXAM**

x²  - 15/x = 4

=> x³ - 15 = 4x

=> x³ - 4x -15 = 0

=> (x-3)(x² + 3x + 5) = 0

x-3 ≠ 0 as x≠3

so x² + 3x + 5 = 0

=> x² + 3x = -5

x(x+1)(x+2)(x+3)

= (x+1)(x+2) x(x+3)

= (x² + 3x + 2)(x² + 3x)

putting value of  x² + 3x = -5

= (-5 +2)(-5)

= (-3)(-5)

= 15

x(x+1)(x+2)(x+3) = 15

option b is correct

Answer 2

Answer:

Step-by-step explanation:

X2_15 x 3x