Question

please let me know if you get this answer please try and laet me know​

Answer 1

Take the point of intersection of common chord and distance between center as P.

one center as O and other as O' .

and the point of intersection of circles A and B.

Now proove triangle AOO' and BOO' congurent .

By cpct angle AO'P=BO'P

now proove triangle AO'P and triangle BO'P congurent by SAS criteria.

By cpct angle APO' =BPO' but their sum is 180

so angle APO' =900.

take PO' as x and PO as 21-x

now in triangle APO' 102= x2+AP2 ===>AP2=102-X2 ---(1)

in traingle AOP 172=(21-x)2+AP2

================>AP2=172-PO2 ---(2)

By (1) and (2)

172-(21-x)2=102-x2

now by solving we get the value of x=6

now find the value of AP

======> AP2=102-x2

AP=8

as AP=8 so AB=16

hence the length of common chord is 16cm.

Hope it helps!