Question

If x2+2(p+2)x+9p=0 has equal roots, then the values of p are:

Answer 1

eual roots b^2 -4ac=0
compare equation with ax^2+bx+c=0
then a=1 b=2(p+2) c=9p
(2(p+2))^2-4*1*9p=0
4(p^2+4+4p)-4*9p=0
p^2+4+4p-9p=0
p^2-5p+4=0
p^2-4p-1p+4=0
p(p-4)-1(p-4)=0
(p-4)(p-1)=0
p=4 p=1