Math, asked by Dinurathore, 11 months ago

If x²-22x+111 = 0, then what is the value of
(x-8)²-1/(×-8)²= ?​

Answers

Answered by Glooring
14

Answer:

38

Step-by-step explanation:

I think you wanted (x-8)²+1/(x-8)² and not (x-8)²-1/(x-8)².

x^2-22x+111 = 0 \\ \\ (x-8)^2-6x+47 = 0 \\ \\ (x-8)^2-6(x-8)-1 = 0\Big|:(x-8) \\ \\ x-8-6-\dfrac{1}{x-8} = 0 \\ \\ x-8-\dfrac{1}{x-8} = 6 \Big|^2 \\ \\ (x-8)^2-2+\dfrac{1}{(x-8)^2} = 36 \\ \\ \\ (x-8)^2+\dfrac{1}{(x-8)^2} = 38

Answered by mikealphacharlie450
2

Answer:

let (x-8)=k

than x=(k+8)

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