Math, asked by ashagram67, 6 months ago

If x²=( 3/7)‐²÷( 1/7)-³find the value of x​

Answers

Answered by harshitha926594
0

Answer:

 {x}^{2}  =  { (\frac{3}{7}) }^{ - 2}  \div  { (\frac{1}{7}) }^{ - 3}  \\  =  { (\frac{1}{7}) }^{3} \div  { (\frac{3}{7}) }^{2} \\  = { (\frac{1}{7}) }^{3} \times { (\frac{7}{3}) }^{2}  \\  =  \frac{1}{ \cancel7}  \times  \frac{1}{ \cancel7}  \times  \frac{1}{7}  \times  \frac{ \cancel7}{3}  \times  \frac{ \cancel7}{3}  \\    \large{ \boxed{{x}^{2} =  \underline{ \underline{ \frac{1}{63} }}}} \\  \\  {x}^{2}  =  \frac{1}{63}  \\ x =  \sqrt{ \frac{1}{63} }  \\ x =  \frac{1}{ \sqrt{63} }  \\ x =  \frac{1}{ \sqrt{9 \times 7} }  \\ x =  \frac{1}{ \sqrt{ {3}^{2}  \times 7} }  \\   \large{ \boxed{x=  \underline{ \underline{ \frac{1}{3 \sqrt{7} } }}}}

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