Question

If x2+3mx+6 then find the value of m

Answer 1

Step-by-step explanation:

here answer

applied quadractic equation formula

b^2-4ac

d= b^2-4ac

x^2+3mx+6=0

a = 1 ,b = 3m,c =6

d=(3m)^2-4*1*6

d= 9m^2-24=0

9m^2=24

m^2= 24/9

m=✓24/9

Answer 2

The value of m is ±$\dfrac{2\sqrt{2} }{\sqrt{3} }$.

Step-by-step explanation:

The given quadratic Polynomial,

$x^2+3mx+6$

Here, a = 1, b = 3m and c = 6

∴ Discriminant, $D=b^{2} -4ac$

$=(3m)^{2} -4(1)(6)$

$=9m^{2} -4(1)(6)$

∴$9m^{2} -24=0$

⇒$3m^{2} -8=0$ [Dividing both sides by 3, we get]

⇒$3m^{2} =8$

⇒ $m =$±$\dfrac{2\sqrt{2} }{\sqrt{3} }$

Hence, the value of m is ±$\dfrac{2\sqrt{2} }{\sqrt{3} }$.