Math, asked by ayan74, 1 year ago

if x2-3x+1=0,then (x4+3x3+5x2+3x+1)/(x4+1)=?

Answers

Answered by Anonymous
3
the ans is 6.5
hope this will help

ayan74: please give me the steps
Anonymous: factorise the give equation and obtain the zeroes and simply put in the given expression
Answered by syed2020ashaels
0

The answer is \frac{x(x^{3}+3x^{2}+4x+6)}{x^{4} +1}\\.

  • Expressions are simplified when they are rewritten in a concise manner and without any similar phrases. When we combine like terms in an expression and, if necessary, solve all of the specified brackets, we are only left with unlike terms in the simplified expression that cannot be further reduced.
  • Expressions are defined as mathematical statements with a minimum of two terms connected by an addition or subtraction operator and containing either integers, variables, or both. PEMDAS, which stands for Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction, is the generic formula for reducing complex formulas.
  • Employing the exponents' rules to the terms simplifies equations using exponents.

Now, we are given that,

\frac{x^{4}+3x^{3}+5x^{2} +3x+1  }{x^{4} +1}.

Now, we have,

\frac{x^{4}+3x^{3}+4x^{2}+x^{2}+6x-3x+1  }{x^{4} +1}

=\frac{x^{4}+3x^{3}+4x^{2}+6x}{x^{4} +1}\\...(Since x^{2} -3x+1=0)

=\frac{x(x^{3}+3x^{2}+4x+6)}{x^{4} +1}\\

Hence, the answer is \frac{x(x^{3}+3x^{2}+4x+6)}{x^{4} +1}\\.

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