Question

Two different dice are tossed together. Find the probability: (i) of getting a doublet, (ii) of getting a sum of 10

Answer 1

Total no.of possible outcomes = 36
(i) Outcomes favourable for getting a doublet are (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)
Favourable no.of events = 6
Probability of getting doublet = 6/36 =1/6

(ii) Outcomes favourable for getting sum of 10 are (4,6), (5,5), (6,4)
Favourable no. of events = 3
Probability of getting sum of 10 = 3/36 =1/12

Answer 2

Given:

Two dice

To find:

The probability of getting a double

The probability of getting a sum of 10

Solution:

Sample space = ( 1, 0 ), ( 1, 1 ), ( 1, 2 )... ( 6, 6 )

Hence,  

Sample space = 36

To find the probability of getting a doublet,

Outcomes = ( 1, 1 ), ( 2, 2 ).. ( 6, 6 )

Possible outcomes = 6

P (getting a double) = 6 / 36  

Hence, P (getting a double) = 1 / 6

To find the probability of getting a sum of 10,

Possible outcomes = ( 4, 6 ), ( 6, 4 ), ( 5, 5 )  

P (getting a sum of 10 ) =3/36

Hence, P ( getting a sum of 10 ) = 1 / 12

Read more on Brainly.in - https://brainly.in/question/3098561