If x2 + 4x + 10/2x + 5 = x2 + 8x + 20 /
4x + 10 then x : ?
1)2.5 and 0
2)23 and 0
3)-3 and 0
4)2.5 and 0
Answers
Given :- if x² + 4x + 10 / 2x + 5 = x² + 8x + 20 / 4x + 10 , find x = ?
Solution :-
→ (x² + 4x + 10) / (2x + 5) = (x² + 8x + 20) / (4x + 10)
taking 2 common from RHS denominator,
→ (x² + 4x + 10) / (2x + 5) = (x² + 8x + 20) / 2(2x + 5)
(2x + 5) will be cancel from both sides denominator,
→ 2(x² + 4x + 10) = x² + 8x + 20
→ 2x² + 8x + 20 = x² + 8x + 20
→ 2x² - x² + 8x - 8x + 20 - 20 = 0
→ x² = 0
→ x = 0 .
now, again,
→ (x² + 4x + 10) / (2x + 5) = (x² + 8x + 20) / (4x + 10)
multiply by (1/2) both sides ,
→ (x² + 4x + 10) / (4x + 10) = (x² + 8x + 20) / (8x + 20)
using divindo now, we get,
→ [(x² + 4x + 10) - (4x + 10)] / (4x + 10) = [(x² + 8x + 20) - (8x + 20)] / (8x + 20)
→ x²/(4x + 10) = x²/(8x + 20)
x² will be cancel from both sides,
→ 1/(4x + 10) = 1/(8x + 20)
→ 4x + 10 = 8x + 20
→ 8x - 4x = 10 - 20
→ 4x = (-10)
→ x = (-2.5) .
Hence, value of x will be (-2.5 and 0.)
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