if x²+4y²+9z²-4xy-12yz+6xz=0
a)x=2y-3z b)x=y-3z c)2x=y-3z d)x=3y-2z
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Answered by
7
EXPLANATION.
⇒ x² + 4y² + 9z² - 4xy - 12yz + 6xz = 0.
As we know that,
Formula of :
⇒ (x + y + z)² = x² + y² + z² + 2xy + 2yz + 2zx.
Using this formula in the equation, we get.
⇒ x² + (2y)² + (3z)² - 2(2xy) - 2(6yz) + 2(3xz) = 0.
⇒ (x - 2y + 3z)² = 0.
⇒ x - 2y + 3z = 0.
⇒ x = 2y - 3z.
Option [A] is correct answer.
Answered by
1
Answer:
OPT=A
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