Question

if X² +5² + 30²=31² ,then find the value of x​

Answer 1

Answer:

Value of x = -4

Step-by-step explanation:

Given :

x²+5²+30²=31²

To find :

The value of x in this equation

Solution :

$\leadsto\sf{{x}^{2}+{5}^{2}+{30}^{2}={31}^{2}}$

$\leadsto\sf{{x}^{2}+{35}^{2}={31}^{2}}$

$\leadsto\sf{{x}^{2}={31}^{2}-{35}^{2}}$

$\leadsto\sf{{x}^{2}=-{4}^{2}}$

$\leadsto\sf{x=\sqrt{{-4}^{2}}}$

$\leadsto\sf{x=-4}$

So , the value of x is -4 .

Answer 2

Given:

• x² + 5² + 30² = 31²

To Find:

• Value of x

Solution:

→ x² + 5² + 30² = 31²

→ x² + (5 + 30)² = 31²

→ x² + 35² = 31²

→ x² = 31² - 35²

→ x² = -4²

→ x = √-4

→ x = -4

Hence,

• Value of x = -4.