If x2 -5x-1=0 then find x2+1÷x2
Answers
Answered by
8
x²–5x^-1=0
x²–5/x=0
(x³–5)/x=0
x³=5
x=5⅓
x²+1/x² »»»› 5⅔+ 1/5⅔
==> (5^4/3 +1)/5^2/3
x²–5/x=0
(x³–5)/x=0
x³=5
x=5⅓
x²+1/x² »»»› 5⅔+ 1/5⅔
==> (5^4/3 +1)/5^2/3
Similar questions