Question

if x²+8y+y³=64,then dy/dx=?​

Answer 1

Step-by-step explanation:

We have,

$\tt{ {x}^{2} + 8y + {y}^{3} = 64 }$

$\sf{ \implies 2x + 8 \dfrac{dy}{dx} + 3 {y}^{2} \dfrac{dy}{dx} =0 }$

$\sf{ \implies 2x + (3 {y}^{2} + 8) \dfrac{dy}{dx} =0 }$

$\sf{ \implies \dfrac{dy}{dx} = \dfrac{ - 2x}{3 {y}^{2} + 8} }$