If x²+9y²=9 and xy=1, find (2 x +6 y)².
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![= {(2x + 6y)}^{2} = {(2x + 6y)}^{2}](https://tex.z-dn.net/?f=+%3D+%7B%282x+%2B+6y%29%7D%5E%7B2%7D+)
![= > 4 {x}^{2} + 36 {y}^{2} + 48xy = > 4 {x}^{2} + 36 {y}^{2} + 48xy](https://tex.z-dn.net/?f=+%3D+%26gt%3B+4+%7Bx%7D%5E%7B2%7D+%2B+36+%7By%7D%5E%7B2%7D+%2B+48xy)
![= > 4( {x}^{2} + 9 {y}^{2} ) + 48(1) = > 4( {x}^{2} + 9 {y}^{2} ) + 48(1)](https://tex.z-dn.net/?f=+%3D+%26gt%3B+4%28+%7Bx%7D%5E%7B2%7D+%2B+9+%7By%7D%5E%7B2%7D+%29+%2B+48%281%29)
![= > 4(9) + 48 = > 4(9) + 48](https://tex.z-dn.net/?f=+%3D+%26gt%3B+4%289%29+%2B+48)
![36 + 48 36 + 48](https://tex.z-dn.net/?f=36+%2B+48)
![= 84 = 84](https://tex.z-dn.net/?f=+%3D+84)
hope this helps you
please like it and mark as brainlist
I tried my best
hope this helps you
_________❤️________
hope this helps you
please like it and mark as brainlist
iahan144:
if it helps you then please mark as brainlist
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