Math, asked by arupbarai164, 7 months ago

if X2 cot 30 =tan 60 sin 60 cos 30, what is the value of X

Answers

Answered by yanvimehra
1

Answer:

x=√3/2

Step-by-step explanation:

x²cot30=tan60 sin 60 cos 30

x²√3=√3×(√3/2)(√3/2)

x²=(√3/2)(√3/2)

x=√3/2

Answered by abhijeet6574
2

Answer:

 {x}^{2}  \cot(30)  =  \tan(60)  \cos(30)  \sin(60)  \\  =  \sqrt{3}  {x}^{2}  =  \sqrt{3}  \times  \frac{ \sqrt{3} }{2}  \times  \frac{ \sqrt{3} }{2}  \\  =  \sqrt{3}  {x}^{2}  =  \frac{3 \sqrt{3} }{2}  \\  =  {x}^{2}  =  \frac{3 \sqrt{3} }{2 \times  \sqrt{3} }  \\  =  {x}^{2}  =  \frac{3}{2}  \\ x =  +   \sqrt{ \frac{3}{2} }  \: or \:  -  \sqrt{ \frac{3}{2} }

Hope it helps mAtE......

Similar questions