Question

If x2+kx-16=0 has equal roots then the value of K is

Answer 1

Answer:

Given equation,

x² + kx + 16 = 0

According to,

D = B² - 4AC

k² - 4 × 1 × 16

k² = 64

If D > 0 , it will have real roots.

D > 0 => K² - 64 > 0

k² > 64

k > +8 or -8 !!

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vishalpatil12345 Ambitious

Solution.......

x2 + kx + 16 = 0

D is equal to or greater than 0

b2 - 4ac is equal to or greater than 0

k2 - 64 = > 0

k2 = > 64

k = > 8

k = 8

Answer 2

Answer:

given equation has imaginary roots

We can do it in two diff. ways

method --1

1. sum of the roots = -b/a

• p+p = -k
• 2p = -k
• p= -k/2
• product of roots = c/a
• p^2 = -16
• p= 4i

then

4i = k/2

then k= +- 8i