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If 2 and -2 are zeros of polynomial p(X)=ax^4+2x^3-3x^2+bx-a
Find value of a and b
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Answer:
a=7/15, b=-11/2
Step-by-step explanation:
substitutes 2 first
a(16)+2(8)-3(4)+b(2)-a=0
16a+4+2b-a=0
15a+2b=-4 this is equation 1
now substitute -2
a(16)+2(-8)-3(4)-2b-a=0
15a-16-12-2b=0
15a-2b=18 and this is equation 2
add equation 1 and 2
30a=14
a=14/30
a=7/15
substitute a in equation 1
15(7/15)+2b=-4
7+2b=-4
2b=-11
b=-11/2
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