Math, asked by Mayankrajpoot, 11 months ago

Pls please please please please please please please please please please answer
If 2 and -2 are zeros of polynomial p(X)=ax^4+2x^3-3x^2+bx-a
Find value of a and b

Answers

Answered by bushra01
2

Answer:

a=7/15, b=-11/2

Step-by-step explanation:

substitutes 2 first

a(16)+2(8)-3(4)+b(2)-a=0

16a+4+2b-a=0

15a+2b=-4 this is equation 1

now substitute -2

a(16)+2(-8)-3(4)-2b-a=0

15a-16-12-2b=0

15a-2b=18 and this is equation 2

add equation 1 and 2

30a=14

a=14/30

a=7/15

substitute a in equation 1

15(7/15)+2b=-4

7+2b=-4

2b=-11

b=-11/2

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